VLSM 192.168.10.0/25
📌 Soal VLSM
Network: 192.168.10.0/25
Kebutuhan host:
- Subnet A = 60 host
- Subnet B = 24 host
- Subnet C = 12 host
- Subnet D = 5 host
Tentukan alokasi subnet menggunakan VLSM dan buat diagram visual / tree alur perhitungan.
🧮 Step 1 & 2: Tentukan Prefix & Urutkan
Rumus: Jumlah host usable = 2^(32 - prefix) - 2
| Subnet | Host Needed | Prefix Needed | Usable Hosts |
|---|---|---|---|
| A | 60 | /26 | 62 |
| B | 24 | /27 | 30 |
| C | 12 | /28 | 14 |
| D | 5 | /29 | 6 |
Urutkan dari terbesar → terkecil: A → B → C → D
📌 Step 3: Alokasi Subnet
Blok awal: 192.168.10.0/25 (0–127)
- Subnet A (60 host) → /26 → 192.168.10.0/26 → Usable: 192.168.10.1–62, Broadcast: 192.168.10.63
- Subnet B (24 host) → /27 → 192.168.10.64/27 → Usable: 192.168.10.65–94, Broadcast: 192.168.10.95
- Subnet C (12 host) → /28 → 192.168.10.96/28 → Usable: 192.168.10.97–110, Broadcast: 192.168.10.111
- Subnet D (5 host) → /29 → 192.168.10.112/29 → Usable: 192.168.10.113–118, Broadcast: 192.168.10.119
- Cadangan → 192.168.10.120–127
🌳 Step 4: Diagram Visual / Tree
- 192.168.10.0/25 (0 - 127)
- ├─ [Subnet A] 192.168.10.0/26 (0 - 63) -> 60 host
- ├─ [Subnet B] 192.168.10.64/27 (64 - 95) -> 24 host
- ├─ [Subnet C] 192.168.10.96/28 (96 - 111) -> 12 host
- └─ [Subnet D] 192.168.10.112/29 (112 - 119) -> 5 host
- └─ [Cadangan] 192.168.10.120/29 (120 - 127)
📊 Step 5: Tabel Ringkas
| Subnet | Prefix | Network | Usable Range | Broadcast | Total Addr | Usable Hosts |
|---|---|---|---|---|---|---|
| A | /26 | 192.168.10.0 | 192.168.10.1-62 | 192.168.10.63 | 64 | 62 |
| B | /27 | 192.168.10.64 | 192.168.10.65-94 | 192.168.10.95 | 32 | 30 |
| C | /28 | 192.168.10.96 | 192.168.10.97-110 | 192.168.10.111 | 16 | 14 |
| D | /29 | 192.168.10.112 | 192.168.10.113-118 | 192.168.10.119 | 8 | 6 |
🚀 CREATED BY KAMARUL ARIFIN MUZAFFAR 🚀
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